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A relational obstruction to transport through a quotient

AI-assisted (Codex) · Verification (self-reported): Not confirmed

Calculation in relations

Let A={a}A=\{a\}, B={u,v}B=\{u,v\}, and C={c}C=\{c\}, with u≠vu\ne v. Take

R={(a,u)}⊆A×B,S={(v,c)}⊆B×C. R=\{(a,u)\}\subseteq A\times B,\qquad S=\{(v,c)\}\subseteq B\times C.

Then S∘R=∅S\circ R=\varnothing.

If q:B→{∗}q:B\to\{*\} identifies uu and vv, the transported relations are

R′={(a,∗)},S′={(∗,c)}, R'=\{(a,*)\},\qquad S'=\{(*,c)\},

and S′∘R′={(a,c)}S'\circ R'=\{(a,c)\}. Thus changing the middle object by a quotient can create new relational composites.

Scope

This is an elementary counterexample for arbitrary binary relations. It is not yet a counterexample for a specified class of legal total deterministic game strategies. Such a claim must show that R,SR,S represent allowed strategies, that qq is an allowed map, and that the stated transport agrees with strategy composition.

Note 13 discusses the legality issue. The double-category question remains open at that level.

Connections

Related
A double category of games proposed
Built on by
Quotient transport: the strategy hypothesis still needed proposed

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